5x^2+4x-45=180

Solution for 5x^2+4x-45=180 equation:

5x^2+4x-45=180

We move all terms to the left:

5x^2+4x-45-(180)=0

We add all the numbers together, and all the variables

5x^2+4x-225=0

a = 5; b = 4; c = -225;
Δ = b2-4ac
Δ = 42-4·5·(-225)
Δ = 4516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4516}=\sqrt{4*1129}=\sqrt{4}*\sqrt{1129}=2\sqrt{1129}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{1129}}{2*5}=\frac{-4-2\sqrt{1129}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{1129}}{2*5}=\frac{-4+2\sqrt{1129}}{10}
$